4(m-1)=(m+1)+12

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Solution for 4(m-1)=(m+1)+12 equation: 



4(m-1)=(m+1)+12

We move all terms to the left:

4(m-1)-((m+1)+12)=0

We multiply parentheses

4m-((m+1)+12)-4=0



We calculate terms in parentheses: -((m+1)+12), so:

(m+1)+12

We get rid of parentheses

m+1+12

We add all the numbers together, and all the variables

m+13

Back to the equation:

-(m+13)



We get rid of parentheses

4m-m-13-4=0

We add all the numbers together, and all the variables

3m-17=0

We move all terms containing m to the left, all other terms to the right

3m=17

m=17/3

m=5+2/3

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