4(m-1)=8(m+1)+3

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Solution for 4(m-1)=8(m+1)+3 equation: 



4(m-1)=8(m+1)+3

We move all terms to the left:

4(m-1)-(8(m+1)+3)=0

We multiply parentheses

4m-(8(m+1)+3)-4=0



We calculate terms in parentheses: -(8(m+1)+3), so:

8(m+1)+3

We multiply parentheses

8m+8+3

We add all the numbers together, and all the variables

8m+11

Back to the equation:

-(8m+11)



We get rid of parentheses

4m-8m-11-4=0

We add all the numbers together, and all the variables

-4m-15=0

We move all terms containing m to the left, all other terms to the right

-4m=15

m=15/-4

m=-3+3/4

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