4(m-2)+3m=20

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Solution for 4(m-2)+3m=20 equation: 



4(m-2)+3m=20

We move all terms to the left:

4(m-2)+3m-(20)=0

We add all the numbers together, and all the variables

3m+4(m-2)-20=0

We multiply parentheses

3m+4m-8-20=0

We add all the numbers together, and all the variables

7m-28=0

We move all terms containing m to the left, all other terms to the right

7m=28

m=28/7

m=4

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