4(m-30)=6(2m+6)

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Solution for 4(m-30)=6(2m+6) equation: 



4(m-30)=6(2m+6)

We move all terms to the left:

4(m-30)-(6(2m+6))=0

We multiply parentheses

4m-(6(2m+6))-120=0



We calculate terms in parentheses: -(6(2m+6)), so:

6(2m+6)

We multiply parentheses

12m+36

Back to the equation:

-(12m+36)



We get rid of parentheses

4m-12m-36-120=0

We add all the numbers together, and all the variables

-8m-156=0

We move all terms containing m to the left, all other terms to the right

-8m=156

m=156/-8

m=-19+1/2

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