4(m-4)=2(2m-8)

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Solution for 4(m-4)=2(2m-8) equation:


Simplifying
4(m + -4) = 2(2m + -8)

Reorder the terms:
4(-4 + m) = 2(2m + -8)
(-4 * 4 + m * 4) = 2(2m + -8)
(-16 + 4m) = 2(2m + -8)

Reorder the terms:
-16 + 4m = 2(-8 + 2m)
-16 + 4m = (-8 * 2 + 2m * 2)
-16 + 4m = (-16 + 4m)

Add '16' to each side of the equation.
-16 + 16 + 4m = -16 + 16 + 4m

Combine like terms: -16 + 16 = 0
0 + 4m = -16 + 16 + 4m
4m = -16 + 16 + 4m

Combine like terms: -16 + 16 = 0
4m = 0 + 4m
4m = 4m

Add '-4m' to each side of the equation.
4m + -4m = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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