4(m-5)+3=3(m-1)

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Solution for 4(m-5)+3=3(m-1) equation: 



4(m-5)+3=3(m-1)

We move all terms to the left:

4(m-5)+3-(3(m-1))=0

We multiply parentheses

4m-(3(m-1))-20+3=0



We calculate terms in parentheses: -(3(m-1)), so:

3(m-1)

We multiply parentheses

3m-3

Back to the equation:

-(3m-3)



We add all the numbers together, and all the variables

4m-(3m-3)-17=0

We get rid of parentheses

4m-3m+3-17=0

We add all the numbers together, and all the variables

m-14=0

We move all terms containing m to the left, all other terms to the right

m=14

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