4(n+(n+4))=3(n+2)+5

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Solution for 4(n+(n+4))=3(n+2)+5 equation:


Simplifying
4(n + (n + 4)) = 3(n + 2) + 5

Reorder the terms:
4(n + (4 + n)) = 3(n + 2) + 5

Remove parenthesis around (4 + n)
4(n + 4 + n) = 3(n + 2) + 5

Reorder the terms:
4(4 + n + n) = 3(n + 2) + 5

Combine like terms: n + n = 2n
4(4 + 2n) = 3(n + 2) + 5
(4 * 4 + 2n * 4) = 3(n + 2) + 5
(16 + 8n) = 3(n + 2) + 5

Reorder the terms:
16 + 8n = 3(2 + n) + 5
16 + 8n = (2 * 3 + n * 3) + 5
16 + 8n = (6 + 3n) + 5

Reorder the terms:
16 + 8n = 6 + 5 + 3n

Combine like terms: 6 + 5 = 11
16 + 8n = 11 + 3n

Solving
16 + 8n = 11 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
16 + 8n + -3n = 11 + 3n + -3n

Combine like terms: 8n + -3n = 5n
16 + 5n = 11 + 3n + -3n

Combine like terms: 3n + -3n = 0
16 + 5n = 11 + 0
16 + 5n = 11

Add '-16' to each side of the equation.
16 + -16 + 5n = 11 + -16

Combine like terms: 16 + -16 = 0
0 + 5n = 11 + -16
5n = 11 + -16

Combine like terms: 11 + -16 = -5
5n = -5

Divide each side by '5'.
n = -1

Simplifying
n = -1

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