4(n+1)+(n+3)=5(n+1)

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Solution for 4(n+1)+(n+3)=5(n+1) equation: 



4(n+1)+(n+3)=5(n+1)

We move all terms to the left:

4(n+1)+(n+3)-(5(n+1))=0

We multiply parentheses

4n+(n+3)-(5(n+1))+4=0

We get rid of parentheses

4n+n-(5(n+1))+3+4=0



We calculate terms in parentheses: -(5(n+1)), so:

5(n+1)

We multiply parentheses

5n+5

Back to the equation:

-(5n+5)



We add all the numbers together, and all the variables

5n-(5n+5)+7=0

We get rid of parentheses

5n-5n-5+7=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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