4(n+1)+2n+3=55

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Solution for 4(n+1)+2n+3=55 equation:


Simplifying
4(n + 1) + 2n + 3 = 55

Reorder the terms:
4(1 + n) + 2n + 3 = 55
(1 * 4 + n * 4) + 2n + 3 = 55
(4 + 4n) + 2n + 3 = 55

Reorder the terms:
4 + 3 + 4n + 2n = 55

Combine like terms: 4 + 3 = 7
7 + 4n + 2n = 55

Combine like terms: 4n + 2n = 6n
7 + 6n = 55

Solving
7 + 6n = 55

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 6n = 55 + -7

Combine like terms: 7 + -7 = 0
0 + 6n = 55 + -7
6n = 55 + -7

Combine like terms: 55 + -7 = 48
6n = 48

Divide each side by '6'.
n = 8

Simplifying
n = 8

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