4(n+1)+3(n-4)=n+40

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Solution for 4(n+1)+3(n-4)=n+40 equation: 


Simplifying
4(n + 1) + 3(n + -4) = n + 40

Reorder the terms:
4(1 + n) + 3(n + -4) = n + 40
(1 * 4 + n * 4) + 3(n + -4) = n + 40
(4 + 4n) + 3(n + -4) = n + 40

Reorder the terms:
4 + 4n + 3(-4 + n) = n + 40
4 + 4n + (-4 * 3 + n * 3) = n + 40
4 + 4n + (-12 + 3n) = n + 40

Reorder the terms:
4 + -12 + 4n + 3n = n + 40

Combine like terms: 4 + -12 = -8
-8 + 4n + 3n = n + 40

Combine like terms: 4n + 3n = 7n
-8 + 7n = n + 40

Reorder the terms:
-8 + 7n = 40 + n

Solving
-8 + 7n = 40 + n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
-8 + 7n + -1n = 40 + n + -1n

Combine like terms: 7n + -1n = 6n
-8 + 6n = 40 + n + -1n

Combine like terms: n + -1n = 0
-8 + 6n = 40 + 0
-8 + 6n = 40

Add '8' to each side of the equation.
-8 + 8 + 6n = 40 + 8

Combine like terms: -8 + 8 = 0
0 + 6n = 40 + 8
6n = 40 + 8

Combine like terms: 40 + 8 = 48
6n = 48

Divide each side by '6'.
n = 8

Simplifying
n = 8

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