4(n+1)-(n+2)=

Solution for 4(n+1)-(n+2)= equation:

Simplifying
4(n + 1) + -1(n + 2) = 0

Reorder the terms:
4(1 + n) + -1(n + 2) = 0
(1 * 4 + n * 4) + -1(n + 2) = 0
(4 + 4n) + -1(n + 2) = 0

Reorder the terms:
4 + 4n + -1(2 + n) = 0
4 + 4n + (2 * -1 + n * -1) = 0
4 + 4n + (-2 + -1n) = 0

Reorder the terms:
4 + -2 + 4n + -1n = 0

Combine like terms: 4 + -2 = 2
2 + 4n + -1n = 0

Combine like terms: 4n + -1n = 3n
2 + 3n = 0

Solving
2 + 3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3n = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 3n = 0 + -2
3n = 0 + -2

Combine like terms: 0 + -2 = -2
3n = -2

Divide each side by '3'.
n = -0.6666666667

Simplifying
n = -0.6666666667