4(n+1)-2(n-5)=36n=

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Solution for 4(n+1)-2(n-5)=36n= equation: 



4(n+1)-2(n-5)=36n=

We move all terms to the left:

4(n+1)-2(n-5)-(36n)=0

We add all the numbers together, and all the variables

-36n+4(n+1)-2(n-5)=0

We multiply parentheses

-36n+4n-2n+4+10=0

We add all the numbers together, and all the variables

-34n+14=0

We move all terms containing n to the left, all other terms to the right

-34n=-14

n=-14/-34

n=7/17

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