4(n+1)-5=27

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Solution for 4(n+1)-5=27 equation: 



4(n+1)-5=27

We move all terms to the left:

4(n+1)-5-(27)=0

We add all the numbers together, and all the variables

4(n+1)-32=0

We multiply parentheses

4n+4-32=0

We add all the numbers together, and all the variables

4n-28=0

We move all terms containing n to the left, all other terms to the right

4n=28

n=28/4

n=7

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