4(n+1)=2(n+18)

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Solution for 4(n+1)=2(n+18) equation: 



4(n+1)=2(n+18)

We move all terms to the left:

4(n+1)-(2(n+18))=0

We multiply parentheses

4n-(2(n+18))+4=0



We calculate terms in parentheses: -(2(n+18)), so:

2(n+18)

We multiply parentheses

2n+36

Back to the equation:

-(2n+36)



We get rid of parentheses

4n-2n-36+4=0

We add all the numbers together, and all the variables

2n-32=0

We move all terms containing n to the left, all other terms to the right

2n=32

n=32/2

n=16

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