4(n+1)=3(n-1)

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Solution for 4(n+1)=3(n-1) equation: 



4(n+1)=3(n-1)

We move all terms to the left:

4(n+1)-(3(n-1))=0

We multiply parentheses

4n-(3(n-1))+4=0



We calculate terms in parentheses: -(3(n-1)), so:

3(n-1)

We multiply parentheses

3n-3

Back to the equation:

-(3n-3)



We get rid of parentheses

4n-3n+3+4=0

We add all the numbers together, and all the variables

n+7=0

We move all terms containing n to the left, all other terms to the right

n=-7

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