4(n+2)+8=(n-1)

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Solution for 4(n+2)+8=(n-1) equation:


Simplifying
4(n + 2) + 8 = (n + -1)

Reorder the terms:
4(2 + n) + 8 = (n + -1)
(2 * 4 + n * 4) + 8 = (n + -1)
(8 + 4n) + 8 = (n + -1)

Reorder the terms:
8 + 8 + 4n = (n + -1)

Combine like terms: 8 + 8 = 16
16 + 4n = (n + -1)

Reorder the terms:
16 + 4n = (-1 + n)

Remove parenthesis around (-1 + n)
16 + 4n = -1 + n

Solving
16 + 4n = -1 + n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
16 + 4n + -1n = -1 + n + -1n

Combine like terms: 4n + -1n = 3n
16 + 3n = -1 + n + -1n

Combine like terms: n + -1n = 0
16 + 3n = -1 + 0
16 + 3n = -1

Add '-16' to each side of the equation.
16 + -16 + 3n = -1 + -16

Combine like terms: 16 + -16 = 0
0 + 3n = -1 + -16
3n = -1 + -16

Combine like terms: -1 + -16 = -17
3n = -17

Divide each side by '3'.
n = -5.666666667

Simplifying
n = -5.666666667

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