4(n+2)-3(1-n)=12-(4-3n)

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Solution for 4(n+2)-3(1-n)=12-(4-3n) equation: 



4(n+2)-3(1-n)=12-(4-3n)

We move all terms to the left:

4(n+2)-3(1-n)-(12-(4-3n))=0

We add all the numbers together, and all the variables

4(n+2)-3(-1n+1)-(12-(-3n+4))=0

We multiply parentheses

4n+3n-(12-(-3n+4))+8-3=0



We calculate terms in parentheses: -(12-(-3n+4)), so:

12-(-3n+4)

determiningTheFunctionDomain
-(-3n+4)+12

We get rid of parentheses

3n-4+12

We add all the numbers together, and all the variables

3n+8

Back to the equation:

-(3n+8)



We add all the numbers together, and all the variables

7n-(3n+8)+5=0

We get rid of parentheses

7n-3n-8+5=0

We add all the numbers together, and all the variables

4n-3=0

We move all terms containing n to the left, all other terms to the right

4n=3

n=3/4

n=3/4

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