4(n+2)-4(3n-5)=-28

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Solution for 4(n+2)-4(3n-5)=-28 equation: 


Simplifying
4(n + 2) + -4(3n + -5) = -28

Reorder the terms:
4(2 + n) + -4(3n + -5) = -28
(2 * 4 + n * 4) + -4(3n + -5) = -28
(8 + 4n) + -4(3n + -5) = -28

Reorder the terms:
8 + 4n + -4(-5 + 3n) = -28
8 + 4n + (-5 * -4 + 3n * -4) = -28
8 + 4n + (20 + -12n) = -28

Reorder the terms:
8 + 20 + 4n + -12n = -28

Combine like terms: 8 + 20 = 28
28 + 4n + -12n = -28

Combine like terms: 4n + -12n = -8n
28 + -8n = -28

Solving
28 + -8n = -28

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + -8n = -28 + -28

Combine like terms: 28 + -28 = 0
0 + -8n = -28 + -28
-8n = -28 + -28

Combine like terms: -28 + -28 = -56
-8n = -56

Divide each side by '-8'.
n = 7

Simplifying
n = 7

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