4(n+2)=(n+1)

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Solution for 4(n+2)=(n+1) equation: 



4(n+2)=(n+1)

We move all terms to the left:

4(n+2)-((n+1))=0

We multiply parentheses

4n-((n+1))+8=0



We calculate terms in parentheses: -((n+1)), so:

(n+1)

We get rid of parentheses

n+1

Back to the equation:

-(n+1)



We get rid of parentheses

4n-n-1+8=0

We add all the numbers together, and all the variables

3n+7=0

We move all terms containing n to the left, all other terms to the right

3n=-7

n=-7/3

n=-2+1/3

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