4(n+2)=-2(2n-1)

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Solution for 4(n+2)=-2(2n-1) equation: 



4(n+2)=-2(2n-1)

We move all terms to the left:

4(n+2)-(-2(2n-1))=0

We multiply parentheses

4n-(-2(2n-1))+8=0



We calculate terms in parentheses: -(-2(2n-1)), so:

-2(2n-1)

We multiply parentheses

-4n+2

Back to the equation:

-(-4n+2)



We get rid of parentheses

4n+4n-2+8=0

We add all the numbers together, and all the variables

8n+6=0

We move all terms containing n to the left, all other terms to the right

8n=-6

n=-6/8

n=-3/4

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