4(n+2)=-60-2(n-7)

Solution for 4(n+2)=-60-2(n-7) equation:

4(n+2)=-60-2(n-7)

We move all terms to the left:

4(n+2)-(-60-2(n-7))=0

We multiply parentheses

4n-(-60-2(n-7))+8=0


We calculate terms in parentheses: -(-60-2(n-7)), so:

-60-2(n-7)

determiningTheFunctionDomain
-2(n-7)-60

We multiply parentheses

-2n+14-60

We add all the numbers together, and all the variables

-2n-46

Back to the equation:

-(-2n-46)


We get rid of parentheses

4n+2n+46+8=0

We add all the numbers together, and all the variables

6n+54=0

We move all terms containing n to the left, all other terms to the right

6n=-54

n=-54/6

n=-9