4(n+2)=14-2(3-2n)

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Solution for 4(n+2)=14-2(3-2n) equation: 



4(n+2)=14-2(3-2n)

We move all terms to the left:

4(n+2)-(14-2(3-2n))=0

We add all the numbers together, and all the variables

4(n+2)-(14-2(-2n+3))=0

We multiply parentheses

4n-(14-2(-2n+3))+8=0



We calculate terms in parentheses: -(14-2(-2n+3)), so:

14-2(-2n+3)

determiningTheFunctionDomain
-2(-2n+3)+14

We multiply parentheses

4n-6+14

We add all the numbers together, and all the variables

4n+8

Back to the equation:

-(4n+8)



We get rid of parentheses

4n-4n-8+8=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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