4(n+2)=2(n-3)

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Solution for 4(n+2)=2(n-3) equation:


Simplifying
4(n + 2) = 2(n + -3)

Reorder the terms:
4(2 + n) = 2(n + -3)
(2 * 4 + n * 4) = 2(n + -3)
(8 + 4n) = 2(n + -3)

Reorder the terms:
8 + 4n = 2(-3 + n)
8 + 4n = (-3 * 2 + n * 2)
8 + 4n = (-6 + 2n)

Solving
8 + 4n = -6 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
8 + 4n + -2n = -6 + 2n + -2n

Combine like terms: 4n + -2n = 2n
8 + 2n = -6 + 2n + -2n

Combine like terms: 2n + -2n = 0
8 + 2n = -6 + 0
8 + 2n = -6

Add '-8' to each side of the equation.
8 + -8 + 2n = -6 + -8

Combine like terms: 8 + -8 = 0
0 + 2n = -6 + -8
2n = -6 + -8

Combine like terms: -6 + -8 = -14
2n = -14

Divide each side by '2'.
n = -7

Simplifying
n = -7

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