4(n+2)=27+n

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Solution for 4(n+2)=27+n equation: 



4(n+2)=27+n

We move all terms to the left:

4(n+2)-(27+n)=0

We add all the numbers together, and all the variables

4(n+2)-(n+27)=0

We multiply parentheses

4n-(n+27)+8=0

We get rid of parentheses

4n-n-27+8=0

We add all the numbers together, and all the variables

3n-19=0

We move all terms containing n to the left, all other terms to the right

3n=19

n=19/3

n=6+1/3

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