4(n+2)=3(n-4)

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Solution for 4(n+2)=3(n-4) equation:


Simplifying
4(n + 2) = 3(n + -4)

Reorder the terms:
4(2 + n) = 3(n + -4)
(2 * 4 + n * 4) = 3(n + -4)
(8 + 4n) = 3(n + -4)

Reorder the terms:
8 + 4n = 3(-4 + n)
8 + 4n = (-4 * 3 + n * 3)
8 + 4n = (-12 + 3n)

Solving
8 + 4n = -12 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
8 + 4n + -3n = -12 + 3n + -3n

Combine like terms: 4n + -3n = 1n
8 + 1n = -12 + 3n + -3n

Combine like terms: 3n + -3n = 0
8 + 1n = -12 + 0
8 + 1n = -12

Add '-8' to each side of the equation.
8 + -8 + 1n = -12 + -8

Combine like terms: 8 + -8 = 0
0 + 1n = -12 + -8
1n = -12 + -8

Combine like terms: -12 + -8 = -20
1n = -20

Divide each side by '1'.
n = -20

Simplifying
n = -20

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