4(n+3)+11=2n-2

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Solution for 4(n+3)+11=2n-2 equation: 



4(n+3)+11=2n-2

We move all terms to the left:

4(n+3)+11-(2n-2)=0

We multiply parentheses

4n-(2n-2)+12+11=0

We get rid of parentheses

4n-2n+2+12+11=0

We add all the numbers together, and all the variables

2n+25=0

We move all terms containing n to the left, all other terms to the right

2n=-25

n=-25/2

n=-12+1/2

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