4(n+3)+2(n+1)=

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Solution for 4(n+3)+2(n+1)= equation:


Simplifying
4(n + 3) + 2(n + 1) = 0

Reorder the terms:
4(3 + n) + 2(n + 1) = 0
(3 * 4 + n * 4) + 2(n + 1) = 0
(12 + 4n) + 2(n + 1) = 0

Reorder the terms:
12 + 4n + 2(1 + n) = 0
12 + 4n + (1 * 2 + n * 2) = 0
12 + 4n + (2 + 2n) = 0

Reorder the terms:
12 + 2 + 4n + 2n = 0

Combine like terms: 12 + 2 = 14
14 + 4n + 2n = 0

Combine like terms: 4n + 2n = 6n
14 + 6n = 0

Solving
14 + 6n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 6n = 0 + -14

Combine like terms: 14 + -14 = 0
0 + 6n = 0 + -14
6n = 0 + -14

Combine like terms: 0 + -14 = -14
6n = -14

Divide each side by '6'.
n = -2.333333333

Simplifying
n = -2.333333333

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