4(n+3)+2n-10=14

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Solution for 4(n+3)+2n-10=14 equation: 



4(n+3)+2n-10=14

We move all terms to the left:

4(n+3)+2n-10-(14)=0

We add all the numbers together, and all the variables

2n+4(n+3)-24=0

We multiply parentheses

2n+4n+12-24=0

We add all the numbers together, and all the variables

6n-12=0

We move all terms containing n to the left, all other terms to the right

6n=12

n=12/6

n=2

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