4(n+3)+4(n-1)=20

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Solution for 4(n+3)+4(n-1)=20 equation:


Simplifying
4(n + 3) + 4(n + -1) = 20

Reorder the terms:
4(3 + n) + 4(n + -1) = 20
(3 * 4 + n * 4) + 4(n + -1) = 20
(12 + 4n) + 4(n + -1) = 20

Reorder the terms:
12 + 4n + 4(-1 + n) = 20
12 + 4n + (-1 * 4 + n * 4) = 20
12 + 4n + (-4 + 4n) = 20

Reorder the terms:
12 + -4 + 4n + 4n = 20

Combine like terms: 12 + -4 = 8
8 + 4n + 4n = 20

Combine like terms: 4n + 4n = 8n
8 + 8n = 20

Solving
8 + 8n = 20

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 8n = 20 + -8

Combine like terms: 8 + -8 = 0
0 + 8n = 20 + -8
8n = 20 + -8

Combine like terms: 20 + -8 = 12
8n = 12

Divide each side by '8'.
n = 1.5

Simplifying
n = 1.5

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