4(n+3)=2(2n+6)

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Solution for 4(n+3)=2(2n+6) equation: 



4(n+3)=2(2n+6)

We move all terms to the left:

4(n+3)-(2(2n+6))=0

We multiply parentheses

4n-(2(2n+6))+12=0



We calculate terms in parentheses: -(2(2n+6)), so:

2(2n+6)

We multiply parentheses

4n+12

Back to the equation:

-(4n+12)



We get rid of parentheses

4n-4n-12+12=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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