4(n+3)=2(6+2n)

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Solution for 4(n+3)=2(6+2n) equation: 


Simplifying
4(n + 3) = 2(6 + 2n)

Reorder the terms:
4(3 + n) = 2(6 + 2n)
(3 * 4 + n * 4) = 2(6 + 2n)
(12 + 4n) = 2(6 + 2n)
12 + 4n = (6 * 2 + 2n * 2)
12 + 4n = (12 + 4n)

Add '-12' to each side of the equation.
12 + -12 + 4n = 12 + -12 + 4n

Combine like terms: 12 + -12 = 0
0 + 4n = 12 + -12 + 4n
4n = 12 + -12 + 4n

Combine like terms: 12 + -12 = 0
4n = 0 + 4n
4n = 4n

Add '-4n' to each side of the equation.
4n + -4n = 4n + -4n

Combine like terms: 4n + -4n = 0
0 = 4n + -4n

Combine like terms: 4n + -4n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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