4(n+3)=2(6-2n)

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Solution for 4(n+3)=2(6-2n) equation:



4(n+3)=2(6-2n)
We move all terms to the left:
4(n+3)-(2(6-2n))=0
We add all the numbers together, and all the variables
4(n+3)-(2(-2n+6))=0
We multiply parentheses
4n-(2(-2n+6))+12=0
We calculate terms in parentheses: -(2(-2n+6)), so:
2(-2n+6)
We multiply parentheses
-4n+12
Back to the equation:
-(-4n+12)
We get rid of parentheses
4n+4n-12+12=0
We add all the numbers together, and all the variables
8n=0
n=0/8
n=0

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