4(n+3-2=2(n-1)-(2-7n

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Solution for 4(n+3-2=2(n-1)-(2-7n equation: 



4(n+3-2=2(n-1)-(2-7n

We move all terms to the left:

4(n+3-2-(2(n-1)-(2-7n)=0

We add all the numbers together, and all the variables

4(n+3-2-(2(n-1)-(-7n+2)=0

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