4(n+3/2)=-18

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Solution for 4(n+3/2)=-18 equation:



4(n+3/2)=-18
We move all terms to the left:
4(n+3/2)-(-18)=0
We add all the numbers together, and all the variables
4(+n+3/2)-(-18)=0
We add all the numbers together, and all the variables
4(+n+3/2)+18=0
We multiply parentheses
4n+18+3/2*4=0
We multiply all the terms by the denominator
4n*2*4+3+18*2*4=0
We add all the numbers together, and all the variables
4n*2*4+147=0
Wy multiply elements
32n*4+147=0
Wy multiply elements
128n+147=0
We move all terms containing n to the left, all other terms to the right
128n=-147
n=-147/128
n=-1+19/128

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