4(n+4)+3n=7(n+2)-2

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Solution for 4(n+4)+3n=7(n+2)-2 equation: 



4(n+4)+3n=7(n+2)-2

We move all terms to the left:

4(n+4)+3n-(7(n+2)-2)=0

We add all the numbers together, and all the variables

3n+4(n+4)-(7(n+2)-2)=0

We multiply parentheses

3n+4n-(7(n+2)-2)+16=0



We calculate terms in parentheses: -(7(n+2)-2), so:

7(n+2)-2

We multiply parentheses

7n+14-2

We add all the numbers together, and all the variables

7n+12

Back to the equation:

-(7n+12)



We add all the numbers together, and all the variables

7n-(7n+12)+16=0

We get rid of parentheses

7n-7n-12+16=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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