4(n+4)-3(n-3)=18

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Solution for 4(n+4)-3(n-3)=18 equation:


Simplifying
4(n + 4) + -3(n + -3) = 18

Reorder the terms:
4(4 + n) + -3(n + -3) = 18
(4 * 4 + n * 4) + -3(n + -3) = 18
(16 + 4n) + -3(n + -3) = 18

Reorder the terms:
16 + 4n + -3(-3 + n) = 18
16 + 4n + (-3 * -3 + n * -3) = 18
16 + 4n + (9 + -3n) = 18

Reorder the terms:
16 + 9 + 4n + -3n = 18

Combine like terms: 16 + 9 = 25
25 + 4n + -3n = 18

Combine like terms: 4n + -3n = 1n
25 + 1n = 18

Solving
25 + 1n = 18

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + 1n = 18 + -25

Combine like terms: 25 + -25 = 0
0 + 1n = 18 + -25
1n = 18 + -25

Combine like terms: 18 + -25 = -7
1n = -7

Divide each side by '1'.
n = -7

Simplifying
n = -7

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