4(n+4)=4(2n-1)

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Solution for 4(n+4)=4(2n-1) equation: 



4(n+4)=4(2n-1)

We move all terms to the left:

4(n+4)-(4(2n-1))=0

We multiply parentheses

4n-(4(2n-1))+16=0



We calculate terms in parentheses: -(4(2n-1)), so:

4(2n-1)

We multiply parentheses

8n-4

Back to the equation:

-(8n-4)



We get rid of parentheses

4n-8n+4+16=0

We add all the numbers together, and all the variables

-4n+20=0

We move all terms containing n to the left, all other terms to the right

-4n=-20

n=-20/-4

n=+5

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