4(n+5)=1/2(4n-12)

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Solution for 4(n+5)=1/2(4n-12) equation:



4(n+5)=1/2(4n-12)
We move all terms to the left:
4(n+5)-(1/2(4n-12))=0
Domain of the equation: 2(4n-12))!=0
n∈R
We multiply parentheses
4n-(1/2(4n-12))+20=0
We multiply all the terms by the denominator
4n*2(4n-12))-(1+20*2(4n-12))=0
Wy multiply elements
8n^2(4+40n(4=0

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