4(n+5)=1/2(4n-12)

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Solution for 4(n+5)=1/2(4n-12) equation: 



4(n+5)=1/2(4n-12)

We move all terms to the left:

4(n+5)-(1/2(4n-12))=0



Domain of the equation: 2(4n-12))!=0

n∈R



We multiply parentheses

4n-(1/2(4n-12))+20=0

We multiply all the terms by the denominator


4n*2(4n-12))-(1+20*2(4n-12))=0

Wy multiply elements

8n^2(4+40n(4=0

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