4(n+7)+7=12(n-5)-1

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Solution for 4(n+7)+7=12(n-5)-1 equation: 



4(n+7)+7=12(n-5)-1

We move all terms to the left:

4(n+7)+7-(12(n-5)-1)=0

We multiply parentheses

4n-(12(n-5)-1)+28+7=0



We calculate terms in parentheses: -(12(n-5)-1), so:

12(n-5)-1

We multiply parentheses

12n-60-1

We add all the numbers together, and all the variables

12n-61

Back to the equation:

-(12n-61)



We add all the numbers together, and all the variables

4n-(12n-61)+35=0

We get rid of parentheses

4n-12n+61+35=0

We add all the numbers together, and all the variables

-8n+96=0

We move all terms containing n to the left, all other terms to the right

-8n=-96

n=-96/-8

n=+12

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