4(n+n+3)+1=9(n+2)

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Solution for 4(n+n+3)+1=9(n+2) equation:


Simplifying
4(n + n + 3) + 1 = 9(n + 2)

Reorder the terms:
4(3 + n + n) + 1 = 9(n + 2)

Combine like terms: n + n = 2n
4(3 + 2n) + 1 = 9(n + 2)
(3 * 4 + 2n * 4) + 1 = 9(n + 2)
(12 + 8n) + 1 = 9(n + 2)

Reorder the terms:
12 + 1 + 8n = 9(n + 2)

Combine like terms: 12 + 1 = 13
13 + 8n = 9(n + 2)

Reorder the terms:
13 + 8n = 9(2 + n)
13 + 8n = (2 * 9 + n * 9)
13 + 8n = (18 + 9n)

Solving
13 + 8n = 18 + 9n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-9n' to each side of the equation.
13 + 8n + -9n = 18 + 9n + -9n

Combine like terms: 8n + -9n = -1n
13 + -1n = 18 + 9n + -9n

Combine like terms: 9n + -9n = 0
13 + -1n = 18 + 0
13 + -1n = 18

Add '-13' to each side of the equation.
13 + -13 + -1n = 18 + -13

Combine like terms: 13 + -13 = 0
0 + -1n = 18 + -13
-1n = 18 + -13

Combine like terms: 18 + -13 = 5
-1n = 5

Divide each side by '-1'.
n = -5

Simplifying
n = -5

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