4(n-1)+3n=7(n+2)

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Solution for 4(n-1)+3n=7(n+2) equation: 



4(n-1)+3n=7(n+2)

We move all terms to the left:

4(n-1)+3n-(7(n+2))=0

We add all the numbers together, and all the variables

3n+4(n-1)-(7(n+2))=0

We multiply parentheses

3n+4n-(7(n+2))-4=0



We calculate terms in parentheses: -(7(n+2)), so:

7(n+2)

We multiply parentheses

7n+14

Back to the equation:

-(7n+14)



We add all the numbers together, and all the variables

7n-(7n+14)-4=0

We get rid of parentheses

7n-7n-14-4=0

We add all the numbers together, and all the variables

-18!=0

There is no solution for this equation

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