4(n-1)-2(3n+2)=16

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Solution for 4(n-1)-2(3n+2)=16 equation: 


Simplifying
4(n + -1) + -2(3n + 2) = 16

Reorder the terms:
4(-1 + n) + -2(3n + 2) = 16
(-1 * 4 + n * 4) + -2(3n + 2) = 16
(-4 + 4n) + -2(3n + 2) = 16

Reorder the terms:
-4 + 4n + -2(2 + 3n) = 16
-4 + 4n + (2 * -2 + 3n * -2) = 16
-4 + 4n + (-4 + -6n) = 16

Reorder the terms:
-4 + -4 + 4n + -6n = 16

Combine like terms: -4 + -4 = -8
-8 + 4n + -6n = 16

Combine like terms: 4n + -6n = -2n
-8 + -2n = 16

Solving
-8 + -2n = 16

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -2n = 16 + 8

Combine like terms: -8 + 8 = 0
0 + -2n = 16 + 8
-2n = 16 + 8

Combine like terms: 16 + 8 = 24
-2n = 24

Divide each side by '-2'.
n = -12

Simplifying
n = -12

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