4(n-1)=-5(3+2n)+3n

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Solution for 4(n-1)=-5(3+2n)+3n equation: 



4(n-1)=-5(3+2n)+3n

We move all terms to the left:

4(n-1)-(-5(3+2n)+3n)=0

We add all the numbers together, and all the variables

4(n-1)-(-5(2n+3)+3n)=0

We multiply parentheses

4n-(-5(2n+3)+3n)-4=0



We calculate terms in parentheses: -(-5(2n+3)+3n), so:

-5(2n+3)+3n

We add all the numbers together, and all the variables

3n-5(2n+3)

We multiply parentheses

3n-10n-15

We add all the numbers together, and all the variables

-7n-15

Back to the equation:

-(-7n-15)



We get rid of parentheses

4n+7n+15-4=0

We add all the numbers together, and all the variables

11n+11=0

We move all terms containing n to the left, all other terms to the right

11n=-11

n=-11/11

n=-1

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