4(n-1)=3(n+2)

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Solution for 4(n-1)=3(n+2) equation:


Simplifying
4(n + -1) = 3(n + 2)

Reorder the terms:
4(-1 + n) = 3(n + 2)
(-1 * 4 + n * 4) = 3(n + 2)
(-4 + 4n) = 3(n + 2)

Reorder the terms:
-4 + 4n = 3(2 + n)
-4 + 4n = (2 * 3 + n * 3)
-4 + 4n = (6 + 3n)

Solving
-4 + 4n = 6 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
-4 + 4n + -3n = 6 + 3n + -3n

Combine like terms: 4n + -3n = 1n
-4 + 1n = 6 + 3n + -3n

Combine like terms: 3n + -3n = 0
-4 + 1n = 6 + 0
-4 + 1n = 6

Add '4' to each side of the equation.
-4 + 4 + 1n = 6 + 4

Combine like terms: -4 + 4 = 0
0 + 1n = 6 + 4
1n = 6 + 4

Combine like terms: 6 + 4 = 10
1n = 10

Divide each side by '1'.
n = 10

Simplifying
n = 10

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