4(n-1)=3(n-14)

Solution for 4(n-1)=3(n-14) equation:

Simplifying
4(n + -1) = 3(n + -14)

Reorder the terms:
4(-1 + n) = 3(n + -14)
(-1 * 4 + n * 4) = 3(n + -14)
(-4 + 4n) = 3(n + -14)

Reorder the terms:
-4 + 4n = 3(-14 + n)
-4 + 4n = (-14 * 3 + n * 3)
-4 + 4n = (-42 + 3n)

Solving
-4 + 4n = -42 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
-4 + 4n + -3n = -42 + 3n + -3n

Combine like terms: 4n + -3n = 1n
-4 + 1n = -42 + 3n + -3n

Combine like terms: 3n + -3n = 0
-4 + 1n = -42 + 0
-4 + 1n = -42

Add '4' to each side of the equation.
-4 + 4 + 1n = -42 + 4

Combine like terms: -4 + 4 = 0
0 + 1n = -42 + 4
1n = -42 + 4

Combine like terms: -42 + 4 = -38
1n = -38

Divide each side by '1'.
n = -38

Simplifying
n = -38