4(n-12)-n=-6+4(n-10)

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Solution for 4(n-12)-n=-6+4(n-10) equation: 



4(n-12)-n=-6+4(n-10)

We move all terms to the left:

4(n-12)-n-(-6+4(n-10))=0

We add all the numbers together, and all the variables

-1n+4(n-12)-(-6+4(n-10))=0

We multiply parentheses

-1n+4n-(-6+4(n-10))-48=0



We calculate terms in parentheses: -(-6+4(n-10)), so:

-6+4(n-10)

determiningTheFunctionDomain
4(n-10)-6

We multiply parentheses

4n-40-6

We add all the numbers together, and all the variables

4n-46

Back to the equation:

-(4n-46)



We add all the numbers together, and all the variables

3n-(4n-46)-48=0

We get rid of parentheses

3n-4n+46-48=0

We add all the numbers together, and all the variables

-1n-2=0

We move all terms containing n to the left, all other terms to the right

-n=2

n=2/-1

n=-2

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