4(n-12)=12(n-4)

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Solution for 4(n-12)=12(n-4) equation:


Simplifying
4(n + -12) = 12(n + -4)

Reorder the terms:
4(-12 + n) = 12(n + -4)
(-12 * 4 + n * 4) = 12(n + -4)
(-48 + 4n) = 12(n + -4)

Reorder the terms:
-48 + 4n = 12(-4 + n)
-48 + 4n = (-4 * 12 + n * 12)
-48 + 4n = (-48 + 12n)

Add '48' to each side of the equation.
-48 + 48 + 4n = -48 + 48 + 12n

Combine like terms: -48 + 48 = 0
0 + 4n = -48 + 48 + 12n
4n = -48 + 48 + 12n

Combine like terms: -48 + 48 = 0
4n = 0 + 12n
4n = 12n

Solving
4n = 12n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12n' to each side of the equation.
4n + -12n = 12n + -12n

Combine like terms: 4n + -12n = -8n
-8n = 12n + -12n

Combine like terms: 12n + -12n = 0
-8n = 0

Divide each side by '-8'.
n = 0

Simplifying
n = 0

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