4(n-2)+2(n+3)=6

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Solution for 4(n-2)+2(n+3)=6 equation: 



4(n-2)+2(n+3)=6

We move all terms to the left:

4(n-2)+2(n+3)-(6)=0

We multiply parentheses

4n+2n-8+6-6=0

We add all the numbers together, and all the variables

6n-8=0

We move all terms containing n to the left, all other terms to the right

6n=8

n=8/6

n=1+1/3

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