4(n-2)-3(n-1)=2(n+6)

Solution for 4(n-2)-3(n-1)=2(n+6) equation:

Simplifying
4(n + -2) + -3(n + -1) = 2(n + 6)

Reorder the terms:
4(-2 + n) + -3(n + -1) = 2(n + 6)
(-2 * 4 + n * 4) + -3(n + -1) = 2(n + 6)
(-8 + 4n) + -3(n + -1) = 2(n + 6)

Reorder the terms:
-8 + 4n + -3(-1 + n) = 2(n + 6)
-8 + 4n + (-1 * -3 + n * -3) = 2(n + 6)
-8 + 4n + (3 + -3n) = 2(n + 6)

Reorder the terms:
-8 + 3 + 4n + -3n = 2(n + 6)

Combine like terms: -8 + 3 = -5
-5 + 4n + -3n = 2(n + 6)

Combine like terms: 4n + -3n = 1n
-5 + 1n = 2(n + 6)

Reorder the terms:
-5 + 1n = 2(6 + n)
-5 + 1n = (6 * 2 + n * 2)
-5 + 1n = (12 + 2n)

Solving
-5 + 1n = 12 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
-5 + 1n + -2n = 12 + 2n + -2n

Combine like terms: 1n + -2n = -1n
-5 + -1n = 12 + 2n + -2n

Combine like terms: 2n + -2n = 0
-5 + -1n = 12 + 0
-5 + -1n = 12

Add '5' to each side of the equation.
-5 + 5 + -1n = 12 + 5

Combine like terms: -5 + 5 = 0
0 + -1n = 12 + 5
-1n = 12 + 5

Combine like terms: 12 + 5 = 17
-1n = 17

Divide each side by '-1'.
n = -17

Simplifying
n = -17