4(n-2)-4(n+2)=n

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Solution for 4(n-2)-4(n+2)=n equation:


Simplifying
4(n + -2) + -4(n + 2) = n

Reorder the terms:
4(-2 + n) + -4(n + 2) = n
(-2 * 4 + n * 4) + -4(n + 2) = n
(-8 + 4n) + -4(n + 2) = n

Reorder the terms:
-8 + 4n + -4(2 + n) = n
-8 + 4n + (2 * -4 + n * -4) = n
-8 + 4n + (-8 + -4n) = n

Reorder the terms:
-8 + -8 + 4n + -4n = n

Combine like terms: -8 + -8 = -16
-16 + 4n + -4n = n

Combine like terms: 4n + -4n = 0
-16 + 0 = n
-16 = n

Solving
-16 = n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
-16 + -1n = n + -1n

Combine like terms: n + -1n = 0
-16 + -1n = 0

Add '16' to each side of the equation.
-16 + 16 + -1n = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1n = 0 + 16
-1n = 0 + 16

Combine like terms: 0 + 16 = 16
-1n = 16

Divide each side by '-1'.
n = -16

Simplifying
n = -16

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